Question

find the area of a rectangle whose perimeter and breadth are 200m and 30m respectively.​

Answer 1

Answer:

Area =length *breadth

=(200*30)m

=6000m

Step-by-step explanation:

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Answer 2

$\LARGE\underline\mathfrak{AnSwEr:}$

$\star$ᴀʀᴇᴀ ᴏғ ʀᴇᴄᴛᴀɴɢʟᴇ ɪs 2100 sǫ.ᴍ

$\LARGE\underline\mathfrak{Step \: by \: step \: explanation :}$

$\large{\sf{\underline{\underline \blue{Given-}}}}$

•ᴘᴇʀɪᴍᴇᴛᴇʀ = 200ᴍ

•ʙʀᴇᴀᴅᴛʜ = 30ᴍ

$\large{\sf{\underline{\underline \blue{To find -}}}}$

•ᴀʀᴇᴀ ᴏғ ʀᴇᴄᴛᴀɴɢʟᴇ

$\large{\sf{\underline{\underline \blue{Figure-}}}}$

$\setlength{\unitlength}{0.78cm}\begin{picture}(12,4)\thicklines\put(5.6,9.1){ A }\put(5.5,5.8){ B }\put(11.1,5.8){ C }\put(11.05,9.1){ D }\put(4.5,7.5){ 30\:m }\put(8.1,5.3){ 70\:m }\put(11.5,7.5){ 30\:m }\put(8.1,9.5){ 70\:m }\put(6,6){\line(1,0){5}}\put(6,9){\line(1,0){5}}\put(11,9){\line(0,-1){3}}\put(6,6){\line(0,1){3}}\end{picture}$

$\large{\sf{\underline{\underline \blue{Solution-}}}}$

➠${\boxed{\sf \red{ Perimter \: = \: 2(length \: + \: breadth) }}}$

ʙʟᴏᴄᴋ ᴛʜᴇ ᴠᴀʟᴜᴇs ɪɴ ᴀᴠᴀɪʟᴀʙʟᴇ ᴅᴀᴛᴀ;

➠$\large\tt\ 200 \: = \: 2( length \: + \: 30)$

➠$\large\tt\frac{200}{2} \: = \: length \: + \: 30$

➠$\large\tt\ 100 \: = \: length \: + \: 30$

➠$\large\tt \ length \: = \: 100 \: - \: 30 \: = \: 70$

➠${\boxed{\sf{Length \: = \: 70m }}}$

ɴᴏᴡ,ᴡᴇ ʜᴀᴠᴇ ᴛᴏ ғɪɴᴅ ᴀʀᴇᴀ ᴏғ ʀᴇᴄᴛᴀɴɢʟᴇ;

➠${\boxed{\sf \red{Area \: = \: length \times\ breadth}}}$

➠$\large\tt\ Area \: = \: 70 \times\ 30$

➠$\large\tt\ Area \: = \: 2100$

➠${\boxed{\sf{Area \: of \: rectangle \: = \: 2100\: m^{2} }}}$