Question

Find the area of a rectangle whose perimeter and length are 280&80m respectively ܓܸܢܠܡܢܠܟܕܝܬܢܬ​

Answer 1

Step-by-step explanation:

Cytoplasm, the semifluid substance of a cell that is external to the nuclear membrane and internal to the cellular membrane, sometimes described as the nonnuclear content of protoplasm. In eukaryotes (i.e., cells having a nucleus), the cytoplasm contains all of the organelles.

Answer 2

Perimeter of rectangle = 280 m

Length of rectangle = 80 m

We know,

$\text{Perimeter of rectangle} \bf = 2(l + b) \\ \\ \large \tt\to2(80 + b) = 280 \\ \\ \large \tt\to80 + b = 140 \\ \\ \large \tt\to \: \: \: \: \: \: b = 140 - 80 \\ \\ \large \tt\to \: \: \: \: \: \: b = 60 \: m$

Now,

Area of rectangle = l × b

→ (80 × 60) m²

→ 4800 m²