Question

Find the area of a rectangle whose sides are (3x-4)and (4x-3) meters

Answer 1

$\huge {\red {\mathfrak {Question:}}}$

• Find the area of the rectangle whose sides are (3x-4) metres and (4x-3) metres.

$\huge{\pink {\mathfrak {Solution:}}}$

$\underline{\bold{Given:}}$

• The length of the rectangle = (4x-3) metres
• The breadth of the rectangle =(3x-4) metres

$\underline{\bold{To\:Find:}}$

• The area of the rectangle.

$\boxed{\orange {Area\: of \:rectangle = Length\times breadth }}$

$= (4x - 3) \times (3x - 4) \\ = 3x(4x - 3) - 4(4x - 3) \\ = 12x ^2 - 9x - 16x + 12 \\ = 12x ^2 - 25x + 12$

$\green {\therefore{The \:area\:of\:the\:rectangle\:is\:(12x ^2 - 25x + 12)sq \:metres.}}$

Answer 2

Answer:

★ Area will be 12x²–25x+12 m² ★

Step-by-step explanation:

Given:

• Sides of rectangle are (3x–4) and (4x–3) metres

To Find:

• Area of rectangle

Solution :

★ We know that the Opposite Side of a rectangle are Equal to each other ★

and,

★ Formula for Area of rectangle = ( Length x Breadth )

$\small\implies{\sf }$ ( 3x – 4 ) ( 4x – 3)

$\small\implies{\sf }$ 3x(4x–3) – 4(4x–3)

$\small\implies{\sf }$ 12x² – 9x – 16x + 12

$\small\implies{\sf }$ 12x² – 25x + 12

Hence, The area of rectangle will be (12x² –25x + 12 ) m²