Math, asked by prosenthilkumar, 11 months ago

Find the area of a rectangle whose sides are 6x^2 and (x+1/x^2

Answers

Answered by ketubh
0

Answer:

6(x + 1)

Step-by-step explanation:

x² will divide 6x² as 6 .

6×(X+1)=

Answered by pkanger
0

Answer:

area of rectangle = 6( x+1 )

Step-by-step explanation:

let the length = 6x^2

and breadth = (x+1 / x^2)

so, area of rectangle = l × b

= (6x^2) (x+1 / x^2)

= 6( x+1 )

Similar questions