Find the area of a rectangle whose width is 2cm less than its length and its perimeter is 12cm
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Answered by
1
A=wl
P=2(l+w)
Solving forA
A=Pw
2﹣w2=12·2
2﹣22=8cm²
I hope it help you
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P=2(l+w)
Solving forA
A=Pw
2﹣w2=12·2
2﹣22=8cm²
I hope it help you
plzzzzz mark me brainliest ans and follow me
Answered by
2
please mark as brainlist answer
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