Math, asked by amansinghx13, 1 year ago

Find the area of a rectangle with length (2x+1) cm and breadth (3x-2) cm.

Answers

Answered by shadowsabers03

$(2x+1)(3x-2) \\ \\ 6x^2-4x+3x-2 \\ \\ 6x^2-x-2$

shadowsabers03: What?!

SwastiJain07: yes if you post too many wrong answers your id may be reported

shadowsabers03: But I didn't post any wrong answer yet.

shadowsabers03: See my profile, bro.

SwastiJain07: i was only telling you

SwastiJain07: and im not bro:) im sis☺

shadowsabers03: Oh, you'd meant that the cause of mistakes in my writing, like 1395 instead of 3195 and 2 instead of -2, is that my id is reported?!

SwastiJain07: no

SwastiJain07: if you continue doing these silly mistakes then it can be reported

shadowsabers03: Oh, I see. Actually those are my mistakes of unconsciousness. Anyway, I'll be care of. Thanking you.

Answered by SwastiJain07

area of rectangle= l×b

So; = (2x+1)(3x-2)

= 6x^2-4x+3x-2

= 6x^2 -x-2

This is the simplified value

I think so you have noted wrong question...Area must be given and the question must be to find the length and breadth..

Hope u will get it..☺

Plz mark it as brainliest☺☺

Thank you☺☺☺

amansinghx13: How did u get 6 in the starting

SwastiJain07: when we multiple 2x from 3 x it become 6x square

Previous Question

Next Question