Math, asked by 91827644040, 17 days ago

find the area of a rectangle with length and breadth are (4pq+2m)and (3mn+4p)​

Answers

Answered by Adrito2
0

Answer:

Area of the rectangle is 4mnpq + 16p²q + 6m²n + 8mp squnit

Step-by-step explanation:

Length of rectangle(l) = (4pq+2m) unit

Breadth of rectangle(b) = (3mn + 4p) unit

So area of rectangle = lb squnit

                                  = (4pq + 2m)(3mn + 4p) squnit

                                  = 4mnpq + 16p²q + 6m²n + 8mp squnit

Ans:- Area of the rectangle is 4mnpq + 16p²q + 6m²n + 8mp squnit

                 

Please do drop a thanks

Answered by rahul123437
0

Find the area of rectangle with length (4pq+2m) and breadth (3mn+4p)

Definition:

The area of the rectangle is equal to the product of length and breadth of the rectangle.

A=l*b

Step-by-step explanation:

[tex]l=(4pq+2m)\\ b=(3mn+4p)[/tex]

[tex]A=l*b\\ =(4pq+2m)*(3mn+4p)\\ =4pq(3mn+4p)+2m(3mn+4p)\\ =13pqmn+16p^{2}q+6m^{2}n+8pm [/tex]

Therefore,the area of rectangle is 13pqmn+16p^{2}q+6m^{2}n+8pm

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