find the area of a rectangle with length and breadth are (4pq+2m)and (3mn+4p)
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Answer:
Area of the rectangle is 4mnpq + 16p²q + 6m²n + 8mp squnit
Step-by-step explanation:
Length of rectangle(l) = (4pq+2m) unit
Breadth of rectangle(b) = (3mn + 4p) unit
So area of rectangle = lb squnit
= (4pq + 2m)(3mn + 4p) squnit
= 4mnpq + 16p²q + 6m²n + 8mp squnit
Ans:- Area of the rectangle is 4mnpq + 16p²q + 6m²n + 8mp squnit
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Find the area of rectangle with length and breadth
Definition:
The area of the rectangle is equal to the product of length and breadth of the rectangle.
Step-by-step explanation:
[tex]l=(4pq+2m)\\ b=(3mn+4p)[/tex]
[tex]A=l*b\\ =(4pq+2m)*(3mn+4p)\\ =4pq(3mn+4p)+2m(3mn+4p)\\ =13pqmn+16p^{2}q+6m^{2}n+8pm [/tex]
Therefore,the area of rectangle is
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