Question

Find the area of a rectangle with one side equal to 4 cm and other is half of it.​

Answer 1

$\huge\mathbb{SOLUTION:-}$

Given

• one side of rectangle which is length

• =Length =4cm

• Breadth=1/2 of length

• Breadth =4/2= 2cm

Now the area of rectangle

$\boxed{\sf{Area\:of\: rectangle=length\times breadth}}$

$\sf\implies Area=4\times 2\\ \\ \sf\implies AREA\:OF\: RECTANGLE=8cm{}^{2}$

$\boxed{\sf{Area\:of\: rectangle=8cm{}^{2}}}$

Answer 2

$\huge{\boxed {\purple {SOLUTION :}}}$

Given :

• Length of the rectangle = 4 cm
• Breadth of the rectangle = (4/2) cm = 2 cm

To Find :

• The area of the rectangle.

$\boxed {\pink{Area=length \times breadth}}$

$\implies Area=length \times breadth \\ \implies Area = 4 \: cm \times 2 \: cm \\ \implies Area = 8 \: cm^2$

Hence,

• $Area\: of\: the\: rectangle=8 \: cm^2$