Question

Find the area of a rectangular park which is 18 3/5 m long and 50/3 m
broad. area of a rectangular park which is 18 3/5 m long and 50/3 m broad.

Answer 1

Given :

• Length of the rectangular park = 18$\sf{\dfrac{3}{5}}$ m
• Breadth of the rectangular park = 50/3 m

To Find :

• The area of the rectangular park

Solution :

Area of a rectangle is given by , Length × breadth.

Substituting the values we have in the formula ,

→ Area = 18$\sf{\dfrac{3}{5}}$ × $\sf{\dfrac{50}{3}}$

→ Area = $\sf{\dfrac{93}{5}}$ × $\sf{\dfrac{50}{3}}$

→ Area = 310 m²

Hence ,

• The area of the given rectangular park is 310 m²

More Formulae :

• Perimeter of rectangle = 2(length + breadth)
• Perimeter of square = 4(side)
• Area of square = (side)²

Answer 2

Answer:

Given :-

Length of the rectangular park = 18 3/5 m

Breadth of the rectangular park = 50/3 m

To Find :-

Area

Solution :-

As we know that

Area = Length × Breadth

$\sf \: Area \: = 18 \dfrac{3}{5} \times \dfrac{50}{3}$

$\sf \: Area \: = \dfrac{90 + 3}{5} \times \dfrac{50}{3}$

$\sf \: Area \: = \dfrac{93}{5} \times \dfrac{50}{3}$

Cancelling 5 by 50 and 93 by 3

$\sf \: Area \: = 31 \times 10$

$\sf \: Area \: = 310 \: {m}^{2}$