Question

find the area of a rectangular park which is 18 3/5m long and 8 2/3m broad​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Correct Question-:

• Find the area of a rectangular park which is $\sf{18 \frac{3}{5}}$m long and $\sf{8 \frac{2}{3}}$m broad .

AnswEr -:

• $\boxed{\sf{\purple{Area\:of\:Square\:-: \frac{806}{5} m² \:or\: 161\frac{1}{5}\:m² }}}$

Explanation-:

Given ,

• The length of Rectangular park is $\sf{18 \frac{3}{5}}$ m .
• The breadth of Rectangular Park is $\sf{8 \frac{2}{3}}$ m .

To Find ,

• Area of Rectangular Park.

☆ Figure related to the question-:

$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(0.03,0.02){\framebox(0.25,0.25)}\put(0.03,2.75){\framebox(0.25,0.25)}\put(4.74,2.75){\framebox(0.25,0.25)}\put(4.74,0.02){\framebox(0.25,0.25)}\multiput(2.1,-0.7)(0,4.2){2}{\sf\large\frac{93}{5}\:m}\multiput(-1.4,1.4)(6.8,0){2}{\sf\large\frac{26}{3} m}\put(-0.5,-0.4){\bf A}\put(-0.5,3.2){\bf D}\put(5.3,-0.4){\bf B}\put(5.3,3.2){\bf C}\end{picture}$

Solution-:

$\boxed{\sf{\blue {Area \: of \: Rectangle-: \: Length \times Breadth }}}$

Here ,

• The length of Rectangular park is $\sf{18 \frac{3}{5}}$ m .

Then , change into improper fraction,

• The length of Rectangular Park is -: $\sf{ \frac{93}{5}}$ m .

Now ,

• The breadth of Rectangular Park is $\sf{8 \frac{2}{3}}$ m .

Then , Change into improper fraction,

• The breadth of Rectangular Park is $\sf{\frac{26}{3}}$ m .

Now ,

$\pink{\sf{\rightarrow {Area\:of\:Rectangle\:-: \frac{93}{5} m \times \frac{26}{3}m }}}$

$\pink{\sf{\rightarrow {Area\:of\:Rectangle\:-: \frac{2418}{15} m² }}}$ [ The fraction is divided by "3"]

$\pink{\sf{\rightarrow {Area\:of\:Rectangle\:-: \frac{806}{5} m²\: or\: 161\frac{1}{5}\:m² }}}$

Hence ,

$\boxed{\sf{\purple{Area\:of\:Square\:-: \frac{806}{5} m² \:or\: 161\frac{1}{5}\:m². }}}$

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