Question

find the area of a rectangular plot one side of which measures 48 M and the diagonal is 50 m

Answer 1

diagonal of a rectangle = Square root of L^2 + B^2
 Here Diagonal = Square root of 48*48 + x*x
                                  2500 = 2304 + x*x
                                  x = 14 
  Area = 48 * 14
          = 672

Answer 2

Hi ,

Let length of the rectangular plot

= l = 48 m

Breadth = b m

Diagonal ( d ) = 50 m

l² + b² = d²

48² + b² = 50²

b² = 50² - 48²

= ( 50 + 48 ) ( 50 - 48 )

= 98 × 2

= 49 × 2 × 2

b = √ ( 7 × 7 ) × ( 2 × 2 )

b = 7 × 2

b = 14 m

Therefore ,

Area of the plot = lb

A = 48 × 14

= 672 sq m
I hope this helps you.

:)