find the area of a rectangular plot one side of which measures 35 cm and the diagonal is 37 CM
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Let ABCD is a rectangular plot , in which BC = 37 cm and CD = 35 cm.
Therefore,
( BC )² = ( CD)² + ( BD)²
( 37)² = (35)² + ( BD)²
( BD)² = (37)² - (35)²
( BD)² = 1369 - 1225
( BD)² = 144
BD = √144 = 12 cm.
Therefore,
Area of rectangular plot = 12 × 35 = 420 cm².
Therefore,
( BC )² = ( CD)² + ( BD)²
( 37)² = (35)² + ( BD)²
( BD)² = (37)² - (35)²
( BD)² = 1369 - 1225
( BD)² = 144
BD = √144 = 12 cm.
Therefore,
Area of rectangular plot = 12 × 35 = 420 cm².
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Q) Find the area of a rectangular plot,one side of which measures 35cm and the diagonal is 37 cm.
Answer:-
The answer is 420 cm²
Explanation-
the b = 35 cm and diagonal= 37 cm which also
gives us two right angled triangle. We know
that
(b)² + (l)² gives us the square of the
hypotenuse.
So, we will reverse it means (h)²- (b)² = (l)²
So, (37)² - (35)² = 1369 - 1225 = 144 which is
the square of 12.
Length = 12
Breadth = 35
Area = 12×35= 420 cm²
Answer:-
The answer is 420 cm²
Explanation-
the b = 35 cm and diagonal= 37 cm which also
gives us two right angled triangle. We know
that
(b)² + (l)² gives us the square of the
hypotenuse.
So, we will reverse it means (h)²- (b)² = (l)²
So, (37)² - (35)² = 1369 - 1225 = 144 which is
the square of 12.
Length = 12
Breadth = 35
Area = 12×35= 420 cm²
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