Question

Find the area
of a rectangular plot, one
side
of which
is 4.8cm
and its
diagonal is so
50 cm​

Answer 1

Step-by-step explanation:

Length of rectangle, l = 48 cm

Let Breadth of rectangle be b

Diagonal of rectangle, d = 50 cm

${d}^{2} = {l}^{2} + {b}^{2} \\ {50}^{2} = {48}^{2} + {b}^{2} \\ {b}^{2} = 2500 - 2304 = 196 \\ b = \sqrt{196} = 14$

Area of rectangle = l × b = 48 × 14 = 672 cm²

Answer 2

Given,

• Diagonal is 50 cm
• One side is 4.8 cm

Basic Concept,

• Opposite sides of Rectangle is always equal.

Diagram ,

• For Diagram refer to the Attachment!!

Solution ,

By Using Pythagoras Theorem

$\;\large{\boxed{\bf{\green{H {}^{2} = B {}^{2} + P {}^{2} }}}}$

Here ⭐ ,

• H is Hypotenuse = 50
• B is Base (Not given ) = B
• P is Perpendicular = 4.8

Putting these values in given Formula

$\rightarrow \sf \: H {}^{2} = B {}^{2} + P {}^{2} \\ \\ \longrightarrow \sf \: 50 {}^{2} = B {}^{2} + 4.8 {}^{2} \\ \\ \longrightarrow \sf B {}^{2} = 4.8 {}^{2} - 50 {}^{2} \\ \\ \longrightarrow \sf \: B = \sqrt{50 {}^{2} - 4.8 {}^{2} } \\ \\ \longrightarrow \sf \: B = \sqrt{2500 - 23.04} \\ \\ \longrightarrow \sf \: B = \sqrt[]{2476.96} \\ \\ : \implies \sf \boxed{ \bf \green{Base = 49.7690}}$

Area of Rectangle

• $\green{\sf A = L × B}$

Here ⭐:

• L is Length = 4.8
• B is Breadth = 49.7690

Putting these values in given formula

$\longrightarrow \bf \boxed{ \bf \: A = L \times B} \\ \rightarrow \sf4.8 \times 49.7690 \\ \sf \: Area \implies \green{\boxed{ \red{238.89 \sf \: cm²}}}$

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