Question

Find the area of a rectangular plot one side of which is 48 m and its diagonal 50 m.​

Answer 1

Step-by-step explanation:

Let ABCD be the rectangular plot.

Then, AB = 48 m and AC = 50 m BC =?

According to Pythagoras theorem,

From right angle triangle ABC,

we have: = AC² = AB²+ BC²

= 502 = 482 + BC²

= BC² = 502 – 482 = BC² = 2500 – 2304

= BC² = 196

= BC = √196

= BC = 14 m

Hence, the area of the rectangle plot = (l × b) Where, l = 48 m, b = 14 m

Then, = (48 × 14) = 672 m²

Answer 2

Answer:

The answer is:

Step-by-step explanation:

Pythagoras property,

(50×50)-(48×48)=Breadth×Breadth

2500-2304=Breadth×Breadth

196=Breadth×Breadth

Breadth=$\sqrt 196$

Breadth=14m

Hence area of rectangle=L×B

                                       =48×14

                                        =672$m^{2}$

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