Question

find the area of a rectangular plot,one side of which is 48 cm and its diagonal is 50 m​

Answer 1

Answer:

${672m}^{2}$

Explanation :

Let ABCD be the rectangular plot.

Then, AB = 48 m and AC = 50 m BC =?

According to Pythagoras theorem,

From right angle triangle ABC, we have:

= AC^2 = AB^2 + BC^2

= 50^2 = 48^2 + BC^2

= BC^2 = 50^2 – 48^2

= BC2 = 2500 – 2304

= BC2 = 196 = BC

= √196 = BC = 14 m

Hence,

the area of the rectangle plot = (l × b)

Where, l = 48 m, b = 14 m

Then,

= (48 × 14)

= 672 m^2