Question

Find the area of a rectangular plot one side of which is 48 m and its diagonal is 50 m .

pls ans me ...​

Answer 1

Answer:

diagonal or hypotenuse=50m

side or base=48m

other side or perpendicular can be found by Pythagoras theorem.

x { }^{2} = \sqrt{} 50 {}^{2} - 48 { }^{2}x

2

=

50

2

−48

2

x= 14m

area of rectangle = length *breadth

=48*14

=672m^2

Step-by-step explanation:

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Answer 2

Answer:

From right angle triangle ABC, we have

= AC2 = AB2 + BC2

= 502 = 482 + BC2

= BC2 = 502 – 482

= BC2 = 2500 – 2304

= BC2 = 196

= BC = √196

= BC = 14

Hence, the area of the rectangle plot = (l × b) Where, l = 48 m, b = 14 m

Then, = (48 × 14) = 672 m2