Question

Find the area of a rectangular plot, one side of which is 48 m and it's diagonal is 50 m. step by step​

Answer 1

Step-by-step explanation:

Given:-

One Side of the the rectangular plot is 48m and it's diagonal is 50 m

To Find:-

Area of the rectangular park When one Side and diagonal is given.

Solution:-

Diagonal or hypotenuse=50m

side or base=48m

other side or perpendicular can be found by Pythagoras theorem.

${x}^{2} = \sqrt{ {50}^{2} } - {48}^{2}$

$= {48}^{14}$

$= {672}^{2}$

Final Answer:-

Therefore the Area of the Rectangular plot is

$= {672}^{2}$

Answer 2

Answer:

GIVEN:

One side of the rectangular plot is 48m and it's diagonal is 50m .

TO FIND:

Area of the rectangular park when one side and diagonal is given .

SOLUTION:

diagonal or hypotenuse = 50m .

Side or base = 48m .

Other side or perpendicular can be found by Pythagoras theorem.

x^2 = √50^2 - 48^2

= 48^14

= 672^2

FINAL ANSWER:

Therefore, The area of the rectangular plot is 672^2 ....

Step-by-step explanation:

@darksoul