Question

find the area of a rectangular plot. one side of which is 48m and its diagnol is 50m​

Answer 1

Answer:

hope it heps

Step-by-step explanation:

Let ABCD be the rectangular plot. Then, AB = 48 m and AC = 50 m BC =? According to Pythagoras theorem, From right angle triangle ABC, we have: = AC2 = AB2 + BC2 = 502 = 482 + BC2 = BC2 = 502 – 482 = BC2 = 2500 – 2304 = BC2 = 196 = BC = √196 = BC = 14 m Hence, the area of the rectangle plot = (l × b) Where, l = 48 m, b = 14 m Then, = (48 × 14) = 672 m2Read more on Sarthaks.com - https://www.sarthaks.com/753570/find-the-area-of-a-rectangle-plot-one-side-of-which-is-48-m-and-its-diagonal-is-50-m

Answer 2

$length^2+ breadth^2=diagonal^2 \\ \\So breadth=\sqrt{50^2−48^2} \\ \\ Breadth=14m \\ Area=48×14=672m^2$