Question

Find the area of a rectangular plot one side of which is 48m
and it's diagonal 50m.

Answer 1

$let \: the \: length \: be \: 48m$
then,
${(width)}^{2} = {(diagonal)}^{2} - {(length)}^{2}$
${(width)}^{2} = {(50)}^{2} - {(48)}^{2} \\ \\ {(width)}^{2} = 2500 - 2304 \\ \\ {(width)}^{2} = 196 \\ = width = \sqrt{196} \\ = width = 14$
Now,
$area \: of \: rectangle = length \times width \\ = (48 \times 14) {m}^{2} \\ = 672 {m}^{2}$



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Answer 2

Answer:

Step-by-step explanation:

Here in this question you will use Pythagoras Theorem to find the other side. Then you will use the formula to calculate area which is length× breath.

See the image