Question

Find the area of a rectangular plot,one side of which is48m and its diagonal is 50 m.

Answer 1

Answer - 672 m2
By
(50)^2 = (48)^2+h^2
2500=2304+h^2
h=√2500-2304
h=14 m

area of triangle =1/2 *b*h
= 1/2 *14*48
=336m2
area of rectangle=336*2
=672m2

Answer 2

$by \: phytagoras \: theorem$
$({given \: side})^{2} = ( {given \: side})^{2} +{diagonals}^{2}$
${adjecent \: side}^{2} = {50}^{2} - {48}^{2}$
$= 2500 - 2304$
$= 196$
$\sqrt{196}$
$= 14$
$area = 48 \times 14$
$672 \: sq.m$