Question

find the area of a regular hexagon in which each side measure 17 cm and its height is 33 CM....please fast

Answer 1

regular hexagon can be divided into 6 equilateral triangles...
area =6(√3/4)(17)(17) CM ^2

Answer 2

The area of a regular hexagon $=\dfrac{867\sqrt{3}}{2}cm^{2}$.

Step-by-step explanation:

Given,

Each side of a regular hexagon(a) = 17 cm and height(h) = 33 cm

To find, the area of a regular hexagon = ?

We know that,

The area of a regular hexagon = 6 × Area of equilateral triangle

$=6\times \dfrac{\sqrt{3}}{4} a^{2}$

$=6\times \dfrac{\sqrt{3}}{4}\times  17^{2}$

$=3\times \dfrac{\sqrt{3}}{2}\times  289cm^{2}$

$=\dfrac{867\sqrt{3}}{2}cm^{2}$

Hence, the area of a regular hexagon$=\dfrac{867\sqrt{3}}{2}cm^{2}$.