find the area of a regular hexagon whose one side is 12m
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Hey mate,
A regular hexagon is composed of six equilateral triangle.
Area of equilateral triangle = √3/4a²
Hence, area of six equilateral triangle = 12√3/4a² which is equal to area of regular hexagon.
Hence area of given regular hexagon
= 12× √3/4 × 4²
=> 12 × √3/4 × 16
=> 12× √3 × 4
=> 83.138 square unit
Hope it will help you.
✨It's. M.S.V.
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A regular hexagon is composed of six equilateral triangle.
Area of equilateral triangle = √3/4a²
Hence, area of six equilateral triangle = 6√3/4a² which is equal to area of regular hexagon.
Hence area of given regular hexagon
= 6 × √3/4 × (12)^²
=> 6 × √3/4 × 144
=374.14
=> 374.14 square unit
Hope it helps dear friend ☺️
saivivek16:
Well, i think 6 should be replaced by 12.
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