Question

Find the area of a regular hexagon whose one side is 4 unit

Answer 1

area of a regular hexagon
= (3√3)/(4) a²
= 3√3(4)(4)/4
= 12√3

therefore, the area of the regular hexagon is 12√3unit²

Answer 2

$\implies$$\large\sf{Area\:of\:∆\:\frac{√3}{4}×{side}^{2}}$

$\implies$$\large\sf{\frac{√3}{4}×{4}^{2}}$

$\implies$$\large\sf{4√3}$

$\longrightarrow$$\large\sf{4√3×6}$

$\longrightarrow$$\large\sf{{24√3cm}^{2}}$