find the area of a regular nonagon with each side of length 9 cm and the perpendicular from its centre to its side measuring 4 CM
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Answer:
A≈500.73 a Side 9
A P
Solution
A=9
4a2cot(180°
9)=9
4·92·cot(180°
9)≈500.72776
Step-by-step explanation:
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