Math, asked by khushikujur25, 2 months ago

find the area of a regular octagon abcdefgh having each side equal to 5cm hc=11cm and al is parallel to hc such that al =4cm​

Answers

Answered by guptaprabhagupta
0

Answer:

40 cm2

Step-by-step explanation:

Answered by anu6843
4

Answer:

Quadrilateral ABCH is a trapezoid: area = (1/2)(4)(11 + 5) = 32 cm²

Quadrilateral HCDG is a rectangle: area = (5)*(11) = 55 cm²

Quadrilateral EFGD is a trapezoid congruent to trapezoid ABCH: area = 32 cm²

Area of regular octagon ABCDEFGH is: (32) + (32) + (55) = 119 cm²

QED

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