Question

find the area of a regular pentagon whose each side is 5 cm long and the radius of the Scribe circle is 3.5 CM solve it please please.​

Answer 1

Answer:

Let us find the area of one of the 5 isosceles triangles in the pentagon.

Side of pentagon a = 5cm

Perpendicular distance between centre of pentagon and the side = 3.5 cm

Area of the traingle = (1/2)*5*3.5 = 8.75 cm²

Therefore, area of pentagon = 8.75 * 5 = 43.75 cm²