Find the area of a regular polygon whose sides are 5cm is and offsets are 4cm each
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Step-by-step explanation:
Area of a regular Octagon=2(1+
2
)a
2
(a)Given:Side=a=4cm
Area of a regular Octagon=2(1+
2
)4
2
=2(1+
2
)×16
=32(1+
2
)
=32(1+1.414)
=32×2.414
=77.248sq.cm
(b)Given:Side=a=5cm
Area of a regular Octagon=2(1+
2
)5
2
=2(1+
2
)×25
=50(1+
2
)
=50(1+1.414)
=50×2.414
=120.7sq.cm
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