Question

find the area of a rhombus ABCD if it's vertices are A (3,0),B (4,5),C (-1,4)and D (-2,-1)

Answer 1

AC=root under (-1-3)^2+(4+0)^2=root under (-4)^2+(4)^2=root under (16+16)=√32
BD=root under (-2-4)^2+(-1-5)^2=root under (36)+(36)=√72
area of rhombus=1/2×(product of diagonals)
=1/2×AC×BD
=1/2×√32×√36
=√1152/2 answer

Answer 2

Answer:

AC=root under (-1-3)^2+(4+0)^2=root under (-4)^2+(4)^2=root under (16+16)=√32

BD=root under (-2-4)^2+(-1-5)^2=root under (36)+(36)=√72

area of rhombus=1/2×(product of diagonals)

=1/2×AC×BD

=1/2×√32×√36

=√1152/2 answer

Step-by-step explanation:

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