Question

find the area of a rhombus each side of which measures 20 cm and one of whose daigonals is 24 cm​

Answer 1

Find Area of Rhombus  

Side = 20 cm  

one diagonal is 24 cm  

• ABCD BC = 24 cm
• so, BM=MC
• 24 /2
• =12cm

diagonals AD=AM+MD

In △AMC, using Pythagoras theorem  

• AC² =AM²+MC²
• (20)² =AM²+(12) ²
• AM² =(20)²+(12)²

• =400−144

• AM²=256  

• AM=  256

• ​AM=16cm  
• AM=MD=16cm

Area of Rhombus =1 /2× Product of diagonal

1/2×(AD.BC)

1/2×((16+16).24)

1/2×32×24

=384cm²

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