Question

Find the area of a rhombus each side of which measures 20 cm and one of whose diagonals is
24 cm.
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Answer 1

Answer:

R.E.F image 

Find Area of Rhombus 

Side = 20 cm 

one diagonal is 24 cm 

→□ABCD BC = 24 cm, so, BM=MC=224=12cm

→ diagonals AD=AM+MD

→In△AMC, using Pythagoras theorem  

AC2=AM2+MC2

(20)2=AM2+(12)2

AM2=(20)2+(12)2

=400−144

AM2=256 

AM=256 

AM=16cm 

→AM=MD=16cm

→ Area of Rhombus =21× Product of diagonal 

=21×(AD.BC)

=21×((16+16).24)

=21×32×24

=384cm2

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