Question

Find the area of a rhombus give that it's side measure 13 cm and one of diagonals measure 10 cm .​

Answer 1

Answer:

130 square cm

Step-by-step explanation:

a rhombus is like a squashed square, so you can do 13*10=130

Answer 2

Answer:

$\large\bf\underline{question}$

Find the area of a rhombus in which its given that it's side measure 13 cm and one of diagonals measure 10 cm.

$\large\bf\underline{given}$

•measure of rhombus= 13cm

•measure of one diagonal of rhombus= 10cm

$\large\bf\underline{to\:find}$

area of the rhombus

$\large\bf\underline{solution}$

to find the area of the rhombus, first we need to find the measure of the other diagonal of the rhombus.

so,given

Side of rhombus= 13cm

length of diagonal AC = 10cm

⛬ OC = 5cm

Since,the diagonals of a rhombus bisect each other at right angles.

So,△BOC is right-angled

Then, by Pythagorus Theorem we have,

⠀ BC²= OC²+OB²

➔ 13² = 5² + OB²

➔OB² = 169 - 25 = 144

➔OB = √144 = 12

hence, diagonal BD = 2×OB = 2×12= 24

so,the measure of the second diagonal of the rhombus is 24

$\bf\underline\pink{area\:of\:the\: rhombus}$:

$area \: of \: rhombus = \frac{1}{2} \times d_{1} \times d_{2}$

$area \: of \: rhombus = \frac{1}{2} \times 10 \times 24 = {12}^{2}$

$\bf\underline\red{hence,\:area\:of\:the\: rhombus\:is\:12²}$