find the area of a rhombus given that it's side measure 13 cm and one of its diagonal measure 10 cm
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AC= 10 cm
AO = OC = 5 cm ( diagonal bisect each other )
in triangle AOB
AB^2 = OA^2+ OB^2
13^2 = 5^2 + OB^2
169 -25 = OB^2
OB = √144=12 cm
BD = 2OB = 24 cm
now
area of Rhombus = 1/2 * D1 *D2
area = 1/2 * 10* 24 = 120 cm^2
AO = OC = 5 cm ( diagonal bisect each other )
in triangle AOB
AB^2 = OA^2+ OB^2
13^2 = 5^2 + OB^2
169 -25 = OB^2
OB = √144=12 cm
BD = 2OB = 24 cm
now
area of Rhombus = 1/2 * D1 *D2
area = 1/2 * 10* 24 = 120 cm^2
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area of a rhombus = to half * product of the diagonals
Rhombus has all the sides equal thus all the sides are of measurement 13 cm
the diagonals of a Rhombus bisect at 90 degree
half of the diagonal equals to 10 divided by 2 equals to 5 cm
then see the picture
hope it helps u
Rhombus has all the sides equal thus all the sides are of measurement 13 cm
the diagonals of a Rhombus bisect at 90 degree
half of the diagonal equals to 10 divided by 2 equals to 5 cm
then see the picture
hope it helps u
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