Find the area of a rhombus given that its side measures 13 cm and one of diagonals
measures 10 cm.
Cind ite altitude,
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Answered by
0
Answer:
120 sqcm
Step-by-step explanation:
From the question,
Rhombus ABCD with centre O,
side (S) = 13 cm
shorter diagnol (P) = 10 cm
consider triangle OCB,
applying Pythagoras theorem,
OC = √ (BC^2 - OB^2 ) = √(169 - 25) = √ 144 = 12
OC = 12 cm
longer diagnol (AC) = AO + OC = 2OC = 2 x 12 = 24
Longer diagnol, AC = 24 cm.
Area of rhombus ABCD = [(AC x BD) / 2 ] = 10 x 24 / 2
Area of Rhombus ABCD = 120 sq.cm
Answered by
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Answer:
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MARK ME AS BRAINLIEST BRO..
Step-by-step explanation:
(´;︵;`)
Attachments:
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