Find the area of a rhombus having each side equal to 20cm and one of its diagonals equal to 24cm
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Answer:
According to the question,
AB = BC = CD = AD = 20 cm
Consider, DB = 24 cm
As diagonals of rhombus bisect each other.
DO = OB = 12 cm
In triangle AOB,
AO2 + OB2 = AB2 =
AO2 + 122 = 202
AO2 = 400 - 144 = 256
Ao=16
diagonalAC=16×2=32
Area of rhombus =
1/2x AC x BD=1/2 x32 x24=384 cm2
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