Question

Find the area of a rhombus having its side equal to 13 cm and one of its diagonals 10 cm. this answer is 120 sand me solution ​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

Let the rhombus be ABCD

The diagonals Ac&BD bisect each other at o

As we know that diagonals of a rhombus bisects each other at right angles.

Take the triangle AOB in which AB is 13cm(given)

And the diagonals Ac is 10cm(given)

so OA=5cm (as diagonals bisect each other in a rhombus)

OB=12cm (by the Pythagoras theorem)

so BD=12+12=24cm

Area of rhombus= d1 x d2= 10x24=240cm^2