Question

find the area of a rhombus having side equal to 13 cm and one of its diagonals 10 cm ​

Answer 1

Before, finding the answer. Let find out on how we can find the answer.

$\boxed{ \sf Area \: of \: Rhombus \: = \dfrac{1}{2} \times d1 \times d2}$

Where,

• D1 is one Diagonal.
• D2 is another Diagonal.

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Given :

• Diagonal One = 13 cm
• Diagonal Two = 10 cm

To find :

• Area of Rhombus

Solution :

$\sf Area \: of \: Rhombus = \dfrac{1}{2} \times d1 \times d2$

$\sf \: = \dfrac{1}{2} \times 13 \times 10$

$\sf = \dfrac{1}{2} \times 130$

$\sf \: = \dfrac{130}{2}$

$\sf = 65$

Hence, the Area of Rhombus is 65 cm.

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★ Know More :

• Perimeter of Rhombus :

4 × a

• All the sides of the rhombus are equal.
• Opposite sides of a rhombus are always parallel.
• Opposite angles of a rhombus are always equal.