Question

find the area of a rhombus having side equal to 13 CM and one of its diagonal is 10cm

Answer 1

I hope this helps you out

Answer 2

The area of a rhombus is $60 cm^{2}.$

Step-by-step explanation:

Given,

Rhombus having equal sides = 13 cm and one of its diagonal($D_{1}$)= 10 cm

Find, the area of rhombus = ?

One of its diagonal$(D_{1})= 10$ cm

∴ Other side of rhombus = $\dfrac{10}{2}$= 5 cm

Using Pythagora's Theorem,

Other diagonal$(D_{2})=\sqrt{13^{2}-5^{2}} =\sqrt{169-25} =\sqrt{144} =12cm$

We know that,

Area of rhombus= × (First diagonal) × (Second diagonal)

=$\dfrac{1}{2}$ × (10) × (12)

= 60 $cm^{2}$

Hence, the area of a rhombus is $60 cm^{2}.$