find the area of a rhombus having side equal to 13 CM and one of its diagonal is 10cm
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area of rhombus = d'd"/2
d'= 10 given
now,
diagonal bisect each other perpendicularly
so, d"/2=√(13^2-5^2) = 12
thus d" = 24
hence,area = 24×10/2=120 cm^2
d'= 10 given
now,
diagonal bisect each other perpendicularly
so, d"/2=√(13^2-5^2) = 12
thus d" = 24
hence,area = 24×10/2=120 cm^2
PatelRitnesh:
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