find the area of a rhombus if each of its sides measures 41cm and one of the diagonals is 80cm.pls solve and explain step by step
Answers
Answered by
1
let quadrilateral ABCD is a rhombus with a diagonal
AC= BD ( diagonal bisect each other of a rhombus )
AREA of Rhombus = AC×CD÷2
= (41 ×41)÷2
= 1681÷2
= 840.5
area of rhombus is 840 square units
pls mark me as brainliest
Answered by
15
Step-by-step explanation:
Area of rhombus =1/2p√4a^2-p^2
= 1/2*80√4*41^2-80^2
=40√324
=40*18
=720
Similar questions