Question

Find the area of a rhombus if the sum of the diagonals is 24 cm and the ratio of two 2 diagonals is 3 : 5.​

Answer 1

Answer:

67.5 cm²

Step-by-step explanation:

Let the ratio of diagonals be 5x and 3x

A/Q

3x+5x=24

8x=24

x=3

The diagonals are =3*3=9,5*3=15

Now , Area of rhombus=1/2*product of diagonals

1/2*(9*15)

1/2*135

67.5

Answer 2

Answer:

67.5

Step-by-step explanation:

First we have to find the diagnols

let ratio 1 diagnol=3x

ratio of 2nd diagnol =5x

therefore 3x+5x=24

8x=24

x=24/8

x=3

1st diagnol =3*3=9

2nd diagnol=3*5=15

area of rhombus=1/2*(diagnol 1*diagnol2)

=1/2(9*15)

=1/2(135)

=67.5