Find the area of a rhombus of 1 side and which measures 20cm and 1 diagonal is 24cm
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Answered by
0
Consider a rhombus ABCD with side length 20cm and diagonal BD 24cm
BP=BD/2=12cm
consider triangle ABP
AP^2=AB^2-BP^2(by Pythagoras theorem)
AP=16
AC=32
area of rhombus=d1*d2/2=AC*BD/2=24*32/2=384cm^2
BP=BD/2=12cm
consider triangle ABP
AP^2=AB^2-BP^2(by Pythagoras theorem)
AP=16
AC=32
area of rhombus=d1*d2/2=AC*BD/2=24*32/2=384cm^2
Answered by
1
Answer:
A = 384cm²
a = Side = 20cm
p = Diagonal = 24 cm
a = pq / 2
a = p² + q² / 2
a = 1 / 2 p √4² - p²
= 1 / 2 • 24 • √ 4.20² - 24² = 384 cm³
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