Question

Find the area of a rhombus of 1 side and which measures 20cm and 1 diagonal is 24cm

Answer 1

Consider a rhombus ABCD with side length 20cm and diagonal BD 24cm

BP=BD/2=12cm

consider triangle ABP

AP^2=AB^2-BP^2(by Pythagoras theorem)

AP=16

AC=32

area of rhombus=d1*d2/2=AC*BD/2=24*32/2=384cm^2

Answer 2

Answer:

A = 384cm²

a = Side = 20cm

p = Diagonal = 24 cm

a = pq / 2

a = p² + q² / 2

a = 1 / 2 p √4² - p²

= 1 / 2 • 24 • √ 4.20² - 24² = 384 cm³