find the area of a rhombus of perimeter 80 cm and one of its diagonal is 24 cm
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Side =x
So perimeter =4x =80
X=20 cm
Rhombus is equal to 2 traingles =
Let abcd a rhombus
Semi perimeter =80/2 =40 cm
Area of Abc = root s (s-a) (s-b) (s-c)
Root 40*40-20*40-20*40-24
Root 40*20*20*16
2*20*20*20*4*4
20*4 *2root 2 *5
160 root 5
So area of bcd =160 root 5
Area of abcd =2*160 root 5
320 root 5 cm square
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