Question

find the area of a rhombus of perimeter 80m and one of whose diagonal is 24 m with diagram​

Answer 1

☆ ANSWER ☆:-

Perimeter = 80 m,

So,

 length of a side =80/4=20m,

 and Diagonal of a rhombus = 24m,

 As, we know that,

The halves of diagonals and a side of a rhombus from a right angled triangle with side as hypotenuse.

Let the length of the other diagonal =2x.

x²+(24/2)²=20²=x²+144=400

x²=400−144=256

x=16

The measure of the another diagonal of the rhombus

= 2*16

=32 m

So, Area of the rhombus

=1/2*Diagonal of a rhombus*Measure of the another diagonal 

A=½×32×24

A=384m²

Answer 2

Step-by-step explanation:

Perimeter = 80 m,

So, length of a side =80/4=20m,

and Diagonal of a rhombus = 24m,

As, we know that,

The halves of diagonals and a side of a rhombus from a right angled triangle with side as hypotenuse.

Let the length of the other diagonal =2x

→X²+(24/2)²=20²=X²+144=400

′→X²=400-144=256

X²=16

•The measure of the another diagonal of the rhombus = 2*16 =32 m

•So, Area of the rhombus =1/2*Diagonal of a rhombus*Measure of the another diagonal

A=1/22X32X34

A=384m²

hope it will help you

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