Question

Find the area of a rhombus one side of which measures 10 cm

and one diagonal 12 cm.​

Answer 1

Given:

• One side of rhombus measures = 10cm
• One of its diagonal = 12cm

To Find:

• The area of Rhombus = ?

Solution:

By using the formula ,

$\boxed {\bold{area = \frac{side \times diagonal}{2}}}$

$\bold{area \: = \frac{ \sqrt{ {p}^{2} + {q}^{2} } }{2}}$

$\bold{area = \frac{1}{2}p \sqrt{4 {a}^{2} - {p}^{2} }} \\ \\ \bold{ = \frac{1} { \cancel2} \times \cancel12 \times \sqrt{4 \times {10}^{2} - {12}^{2} } } \\ \\ \boxed{\bold \red{ = 96cm ^{2}}}$