Question

Find the area of a Rhombus , one side of which measures 20cm and one of whose diagonal is 24cm

Answer 1

Consider a rhombus ABCD with side length 20cm and diagonal BD 24cm

BP=BD/2=12cm

consider triangle ABP

AP^2=AB^2-BP^2(by Pythagoras theorem)

AP=16

AC=32

area of rhombus=d1*d2/2=AC*BD/2=24*32/2=384cm^2

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Answer 2

area of rhombus=diagonal*root side^2-(diagonal/2)^2
area=24*root 20^2-(24/2)^2
area=24*16
area=384 cm^2