find the area of a rhombus, the lengths of whose diagonals are 16cm and 24cm respectively.
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Answered by
8
Area of a rhombus is half the product of the two fiagonals
Therefore
Area=(1/2)×(16)×(24)
=16×12
=192 cm²
Hope it helps...!
Therefore
Area=(1/2)×(16)×(24)
=16×12
=192 cm²
Hope it helps...!
Answered by
5
area of rhombus is 1/2 × length of a diagonal × length of a diagonal .
given length of diagonald are 16cm and 24 cm
so, 1/2×16×24=8×24=192cm^2
given length of diagonald are 16cm and 24 cm
so, 1/2×16×24=8×24=192cm^2
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