find the area of a rhombus where each side mesures 20 cm and one of its diagonal is 32cm
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length of the first diagonal= 32 cm
length of the second diagonal=
by Pythagoras's theorem
here the base = d2/2
perpendicular = 32/2= 16cm
h^2 = b^2 + p^2
=> b^2 = h^2 - p^2
=> b^2 = 20^2 - 16^2
=>b^2 =144
=> b =12
d2 = 2 × b = 2×12= 24 cm
area of a rhombus = d1 × d2 /2
= 24 × 32/2
= 384 sq.cm
length of the second diagonal=
by Pythagoras's theorem
here the base = d2/2
perpendicular = 32/2= 16cm
h^2 = b^2 + p^2
=> b^2 = h^2 - p^2
=> b^2 = 20^2 - 16^2
=>b^2 =144
=> b =12
d2 = 2 × b = 2×12= 24 cm
area of a rhombus = d1 × d2 /2
= 24 × 32/2
= 384 sq.cm
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a two digit numberc of which tens digit exceed unit digit by 5 the number itself is 8 times the sum of its digit find the number
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