Question

find the area of a rhombus whose diagnoals are length 12 cm and 8.2 cm​

Answer 1

Answer:

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$\mathrm{Area \: of \: the \: rhombus = \frac{1}{2} \times \: d_1 \: d_2}$

$\rm{where \: d_1,d_2 \: are \: lengths \:of \: diagonals }$

$\rm{ = \frac{1}{2} \times 10 \times {8.2cm}^{2} }$

$\rm{ = {41cm}^{2} }$

Answer 2

Answer:

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Step-by-step explanation:

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