Find the area of a rhombus whose diagonals are 12.2cm and 9.4cm
vidhu172007:
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Lengths of the diagonals of a rhombus are 11.2 cm and 7.5 cm (Given in que)
So by formula .
Area of rhombus is ;- 1/2 ×d1 ×d2
= 1/2 ×84
= \frac{1}{2} \times 11.2 \times 7.5
= 42 {cm}^{2}
Area of rhombus is 42cm^2
hope it helps...
Answered by
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First diagonal (d¹) = 12.2 cm
Second Diagonal (d²) = 9.4 cm
Area of Rhombus = ½×d¹×d²
Area = ½×12.2×9.4
= 57.34 cm²
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