Question

Find the area of a rhombus whose diagonals are 15.2cm and 24cm respectively. ​

Answer 1

Step-by-step explanation:

we know that area of rhombus = ½ × d1 × d2

here by talking d1 = 15.2, d2 = 24

Area = 1/2 × 15.2 × 24

        =  15.2/2 × 24

        = 7.6 × 24

        = 182.4

               

Answer 2

$\sf \pink{Given}\begin{cases}&\sf{Length\:of\:the\:first\:diagonal\:(d_1)=\bf{15.2\:cm.}} \\ \\ &\sf{Length\:of\:the\:second\:diagonal\:(d_2)=\bf{24\:cm.}} \\ \end{cases}$

To FinD:-

The area of the rhombus.

Solution:-

• We are given the two diagonals of rhombus so we can find the area of rhombus.

We know that,

$\qquad\normalsize{\pink{\underline{\boxed{\sf{Area_{(rhombus)}=\dfrac{1}{2}\times d_1\times d_2}}}}}$

$\sf {Here}\begin{cases}&\sf{d_1=First\:diagonal=\bf{15.2\:cm.}} \\ &\sf{d_2=second\:diagonal=\bf{24\:cm.}} \\ \end{cases}$

• Putting the values,

$\\ :\normalsize\implies{\sf{Area_{(rhombus)}=\dfrac{1}{2}\times15.2\times24}}$

$\\ :\normalsize\implies{\sf{Area_{(rhombus)}=\dfrac{1}{\cancel{2}}\times15.2\times\cancel{24}}}$

$\\ :\normalsize\implies{\sf{Area_{(rhombus)}=1\times15.2\times12}}$

$\\ \qquad\normalsize\therefore\boxed{\mathfrak{\pink{Area_{(rhombus)}=182.4\:cm^2.}}}$

The area of rhombus is 182.4 cm².

Explore More:-

• Area of rectangle = Length × Breadth

• Perimeter of rectangle = 2(Length+Breadth)

• Area of square = side × side

• Perimeter of square = 4 × side

• Area of triangle = 1/2 × base × height

• Area of parallelogram = base × height